View Full Version : OK, Algebra 1 geniuses. I have some probs 4 you...
1cat2ferrets
02-01-2008, 10:37 AM
Here are some problems that my son and I can't figure out. Please help us!!:confused:
1. The square root radical of m multiplied by the square root radical of m^2.
2. The square root radical of m^2/n^3
3. the square root radical of 2 + the square root radical of 2/49
4. Write the following into an equation and solve..
One eighth of the square root of 7 less than a number is 2. What is the number?
I want to thank whoever solves these problems and I'll offer huge amounts of Chocolate in appreciation!!:p
Ailaena
02-01-2008, 10:56 AM
Here are some problems that my son and I can't figure out. Please help us!!:confused:
1. The square root radical of m multiplied by the square root radical of m^2.
2. The square root radical of m^2/n^3
3. the square root radical of 2 + the square root radical of 2/49
4. Write the following into an equation and solve..
One eighth of the square root of 7 less than a number is 2. What is the number?
I want to thank whoever solves these problems and I'll offer huge amounts of Chocolate in appreciation!!:p
Forgive me, I may make this more difficult, but I am sitting here wasting time until dd gets out of class!
First, I am assuming that when you say "square root radical" that you mean just plain old square root of whatever, i.e. x^(1/2). So...
1. m^(1/2) * (m^2)^(1/2) or sqrt m*sqrt m^2 would end up as m sqrt m
or m(m^1/2)
2. Is this like sqrt (m^2/n^3)? I will assume so (Im difficult, sorry)
If so, then the answer would be m/(n sqrt n)
3. (8 sqrt 2)/7 (Look! Im purple now!) Do you me to work it out for you?
4. (sqrt x-7)/8 = 2 ----> (sqrt x-7) = 16 ---> square both sides --->
x-7 = 256 ---> x=263
1cat2ferrets
02-01-2008, 12:07 PM
could you work out number 3 for me? I can't figure out how you got 8 sqr 2/7.
Yes, I meant sq root when I said square root radical because my son is working on radicals .....both rational and irrational. He's usually pretty good, but this chapter is kinda tough.
Thanks for your help!:D
Ailaena
02-01-2008, 12:22 PM
could you work out number 3 for me? I can't figure out how you got 8 sqr 2/7.
Yes, I meant sq root when I said square root radical because my son is working on radicals .....both rational and irrational. He's usually pretty good, but this chapter is kinda tough.
Thanks for your help!:D
NP! I find great solace in solving math problems. Sadly.
3. the square root radical of 2 + the square root radical of 2/49
sqrt2 + sqrt (2/49) ---> sqrt2 + (sqrt2/sqrt49) ---> sqrt 2 + (sqrt 2)/7 --->Now they need common denominators so multiply the first term by 7/7 ---> (7sqrt 2)/7 + (sqrt 2)/7 ---> (7sqrt2 + sqrt2)/7 ---> (8sqrt2)/7
Hope that made sense!
1cat2ferrets
02-01-2008, 03:16 PM
Funny, I had that answer but wasn't sure it was right. Silly.;)
BTW, I love to solve math problems, too. I guess you and I could be called Math dorks, huh?? LOL!!! Just kidding:p
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